Flashcards for topic Light Waves
Explain the concept of optical path and its significance in wave optics
Optical path is the equivalent distance a light wave would travel in vacuum to accumulate the same phase change as it does when traveling through a medium.
For a medium with refractive index and physical distance :
Significance:
Example: A 1 mm glass plate () has an optical path of 1.5 mm.
When analyzing Young's double slit experiment, how does changing each parameter (wavelength, slit separation, and screen distance) affect the interference pattern, and why?
Effects of changing parameters:
Increasing wavelength (λ):
Increasing slit separation (d):
Increasing screen distance (D):
Practical application: When using Young's experiment to measure an unknown wavelength, maximize D and minimize d to create wider, more easily measurable fringes.
Mathematical relationship: w = Dλ/d
What are coherent light sources, why are they necessary for interference experiments, and how do they differ from ordinary light sources?
Coherent Light Sources:
Ordinary Light Sources (incoherent):
Coherent Sources:
In interference experiments:
What happens to the phase of a wave when it reflects from a boundary where the transmission medium has a higher density (or higher wave impedance) than the incident medium?
Example: When light traveling in air reflects from glass or water, the reflected wave experiences a phase shift of π, which affects interference patterns in thin films.
When does a reflected wave maintain its original phase (i.e., experience no phase inversion) upon reflection?
A wave maintains its original phase upon reflection when:
Example: Light traveling inside water that reflects from the water-air interface maintains its original phase because it's moving from higher refractive index (water) to lower refractive index (air).
What mathematical relationship exists between the angle of diffraction (θ) and the position on the observation screen (x) in a Fraunhofer setup?
In single slit diffraction, why does the intensity of secondary maxima decrease so rapidly compared to the central maximum?
Secondary maxima decrease rapidly in intensity because:
The mathematical form of the intensity function causes rapid decline as β increases
Quantitatively:
Physical explanation:
This rapid intensity decrease explains why practical applications focus mainly on the central maximum, as secondary maxima contribute minimally to the overall diffraction pattern.
How does the intensity distribution appear when two point sources are at different states of resolution, and what mathematical relationship defines the transition between these states?
Intensity distribution for two point sources at different resolution states:
Unresolved sources: • Single merged intensity peak • No discernible separation between sources • Peak intensity higher than individual source intensities
Just resolved sources (Rayleigh criterion): • Two peaks with a dip of ~26.5% between them • The mathematical condition: separation equals radius of Airy disk • Angular separation θ = 1.22λ/D
Well resolved sources: • Two distinct peaks with deep valley between them • Minimal interference between diffraction patterns • Intensity distribution closely matches two isolated point sources
The transition is defined by the mathematical relationship: θ = 1.22λ/D (for circular apertures)
The resulting intensity pattern for two equal point sources follows: I(θ) = I₁(θ) + I₂(θ) + 2√(I₁(θ)I₂(θ))cos(Δφ) where I₁ and I₂ are individual Airy patterns and Δφ is the phase difference.
How do the intensity profiles differ between unresolved, just resolved, and well-resolved optical images?
• Unresolved images:
• Just resolved images (Rayleigh limit):
• Well-resolved images:
Derive the mathematical expression for how the intensity of transmitted light varies when linearly polarized light passes through a polaroid with its transmission axis at angle θ to the incident electric field vector.
Law of Malus:
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