Flashcards for topic Magnetic Field Due to A Current
Explain the force between two parallel current-carrying wires and derive the expression for the force per unit length between them.
Force per unit length:
Derivation:
Direction:
Application: This principle defines the ampere. If two parallel wires 1m apart carry equal currents producing a force of N/m, the current is defined as 1 ampere.
Explain the mechanism by which parallel currents attract each other while antiparallel currents repel. Connect this to the definition of the ampere.
Mechanism of attraction/repulsion:
For parallel currents:
For antiparallel currents:
Connection to ampere definition:
Given: A 1 cm wire segment carrying a 10 A current and a point 200 cm away at 45° from the wire.
Calculate the magnitude of the magnetic field at this point, and explain why the distance ratio makes treating the wire as a small element valid in this scenario.
Magnitude of magnetic field:
The approximation of treating the wire as a small element is valid because:
When applying the Biot-Savart Law to various current configurations, how do you determine whether the magnetic field at a point goes into the plane or comes out of the plane?
To determine if the magnetic field goes into or out of a plane:
Identify the direction of current (i) and the position vector (r) from the current element to the point
Apply the right-hand rule to the cross product (dl × r):
Conventional notation:
Example: For a straight current-carrying wire in a plane with current flowing upward, points to the left of the wire experience a magnetic field going into the plane, while points to the right experience a field coming out of the plane.
How does the magnitude of the magnetic field vary with distance from a long, straight current-carrying wire? Calculate the field strength at 10 cm from a wire carrying 2A of current.
The magnetic field magnitude around a long, straight current-carrying wire:
Where:
The field strength decreases inversely with distance from the wire.
For a wire carrying 2A at 10 cm distance: B = (4π × 10⁻⁷ T·m/A)(2A)/(2π × 0.1m) B = (4π × 10⁻⁷ T·m/A)(2A)/(0.2π m) B = 4 × 10⁻⁶ T = 4 μT
Note: Unlike electric fields that radiate outward, magnetic fields circulate around the current.
What is the formula for calculating the magnetic field at an axial point P located at distance d from the center of a circular current loop with radius a carrying current i?
The magnetic field at an axial point is:
Where:
This formula shows that:
How does the magnetic field strength vary at different locations around a circular current loop, and what mathematical relationship governs the axial field?
Magnetic field strength variations around a circular current loop:
On the axis at distance x from center of a loop with radius a:
For points far from the loop (x >> a), this simplifies to:
Where m = ia² is the magnetic dipole moment.
Example: At twice the radius distance from the center along the axis, the field strength drops to about 1/8 of its value at the center.
What does Ampere's Law state about the relationship between magnetic field circulation and electric current?
Ampere's Law states: The circulation of the magnetic field B along a closed, plane curve equals μ₀ times the total current crossing the area bounded by the curve:
Where:
Example: For a long straight wire carrying current I, using a circular path of radius r centered on the wire gives B(2πr) = μ₀I, leading to B = μ₀I/2πr.
What is the relationship between the tangential distance from a straight current-carrying wire and the strength of the magnetic field? Why does this relationship exist?
The magnetic field strength (B) is inversely proportional to the distance (r) from a straight current-carrying wire:
B = μ₀i/(2πr)
This relationship exists because:
This inverse relationship means doubling the distance reduces the field strength by half, and can be verified experimentally by measuring the force on a test charge at various distances.
What is the physical significance of the uniform magnetic field inside a solenoid and the zero field outside, and how does this relate to the current distribution?
Physical significance of solenoid field distribution:
Inside the solenoid:
Outside the solenoid:
Current distribution significance:
This field containment property makes solenoids useful for creating controlled magnetic fields in applications like electromagnets, MRI machines, and particle accelerators.
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